4x^2-152x+1435=0

Solution for 4x^2-152x+1435=0 equation:

4x^2-152x+1435=0

a = 4; b = -152; c = +1435;
Δ = b2-4ac
Δ = -1522-4·4·1435
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-152)-12}{2*4}=\frac{140}{8}
=17+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-152)+12}{2*4}=\frac{164}{8}
=20+1/2
$